Saturday, March 3, 2012

Square and Circle - III

This is a Java Applet created using GeoGebra from www.geogebra.org - it looks like you don't have Java installed, please go to www.java.com
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1 comment:

  1. Πάγκαλος ΠαναγιώτηςMarch 4, 2012 at 6:51 AM

    e=CircularArc[B, C, A]
    E=Intersect[e, Segment[D, B]]
    g=Parabola[E, Segment[C, D]]
    G=Intersect[g, Segment[D, E]]
    Circle[G, E]
    or
    Circle[Intersect[Parabola[Intersect[CircularArc[B, C, A], Segment[D, B]], Segment[C, D]], Segment[D, Intersect[CircularArc[B, C, A], Segment[D, B]]]], Intersect[CircularArc[B, C, A], Segment[D, B]]]

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